#1. $$Ca_3(PO_4)_2+3SiO_2+5C+5O_2+3H_2O\\\rightarrow 3CaSiO_3+5CO_2+2H_3PO_4$$ If equal masses of calcium phosphate (M = 310.0) and silica (M = 60.0) are reacted with excess carbon, oxygen, and water to produce 1.00 x 103 kg phosphoric acid (M = 98.0), what mass of calcium phosphate was used, assuming 100% yield?
1.0×103/0.098 moles of phosphoric acid is produced by 0.5×103/0.098 moles of calcium phosphate, which is equivalent to (0.5×103/0.098)x0.31 or about 1580 kg.
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