The moments of inertia of an octahedral prolate rotor with symmetry (e.g. Pt(NH3) 2Cl4) are characterised by a unique moment of inertia
around the principal axis and two equal moments of inertia
perpendicular to the principal axis, where
. They are derived using simple geometric considerations.
The diagram above shows an octahedral molecule of the type BA4C2, where B is the central atom. The moment of inertia along the -axis is
. Since the four B-A bonds have equal lengths of , we have
Question
Why do and
not contribute to
?
Answer
In general, . Since atoms B and C lie along the rotational axis, the moment of inertia about this axis is effectively zero due to the absence of perpendicular mass displacement (
).
Similarly, the moment of inertia of the molecule about the -axis, which is equal to that about the
-axis, is
. Since the two B-C bonds have equal lengths of
, we have
You’ll find that the expression for the moment of inertia about the -axis is the same as eq36.