Just as the standard reaction enthalpy is
the standard reaction entropy of a system is
where vP and vR are the stoichiometric coefficients of the products and reactants respectively.
The difference between ΔHfo and Smo is that the former is the relative energy between a substance and the constituents of the substance in their reference states, while the latter is the absolute energy of the substance. This is why ΔHfo[C(graphite)] = 0 but Smo[C(graphite)] ≠ 0. Despite the difference, the quantities of ΔHro and ΔSro are comparable, as the zero-enthalpies of reference states in and cancel out when we compute ΔHro (see articles on standard enthalpy change of formation and Hess Law for details).
Question
Calculate the standard reaction entropy of given , and .
Answer
Using eq1,
The positive change in standard reaction entropy of the incomplete combustion of carbon illustrates the dependency of the change in entropy of a system on the change in the number of moles of gas in a reaction. In the above example, the double in number of moles of gas outweighs the removal of a mole of carbon solid in the system, as the increase in the number of moles of gas leads to the dispersal of energy over a greater number of translational energy states of the system. This implies that ΔSro can be negative when we have a reaction that results in a decrease the number of moles of gas.