2nd order reaction of the type (A + 2B → P)

The rate law for the 2nd order reaction of the type A + 2BP is:


Using the same logic described in the previous article, we can rewrite the rate law as:


where a = [A0] and b = [B0].

Rearranging the above equation and integrating throughout, we have

\int_{0}^{x}\frac{dx}{(a-x)(\frac{b}{2}-x)}=2k\int_{0}^{t}dt\; \; \; \; \; \; \; \; 13

Substituting the partial fraction expression \frac{1}{(a-x)(\frac{b}{2}-x)}=\frac{1}{a-\frac{b}{2}}\left ( \frac{1}{\frac{b}{2}-x}-\frac{1}{a-x} \right ) in eq13 and after some algebra, we have,


which is equivalent to



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