Atomic orbital energies are eigenvalues of the Hartree-Fock equations. These eigenvalues are expressed by eq148 and are based on a specific state of the atom. As illustrated in the article on the analytical solution of the Hartree-Fock method for the ground state of Li, we can theoretically compute for any occupied orbital of an atom. For example, of the 2p orbital of Li is determined using the excited electron configuration state of 1s^{2}2p^{1}. In general, for atoms with to are depicted in the diagram below.

For atoms with , their 4s orbital energies lie below their respective 3d orbital energies (see diagram below). An example is the atom with the ground state electron configuration [Ar]4s^{1}. This implies that the theoretical ground state energy of is closer to the experimental value when we use a 4s Slater-type orbital rather than a 3d Slater-type orbital for computing .

With that in mind, one may conclude that the ground state electron configuration of Sc is [Ar]3d^{3}. However, it is [Ar]3d^{1}4s^{2}. This is because the orbital energies and for [Ar]3d^{3 }are different from those for [Ar]3d^{1}4s^{2} (refer to eq148), even though for both configurations. For example, for the electron configurations [Ar]3d^{1}4s^{2 }and [Ar]3d^{2}4s^{2 }are (in Hartree units)

and

respectively, where .

In short, the Hartree-Fock computation using the electron configuration of [Ar]3d^{1}4s^{2 }gives a ground state energy that is closest to experimental values. Qualitatively, we rationalise the above with the fact that 3d orbitals are smaller in size compared to the 4s orbitals. Electrons occupying 3d orbitals therefore experience greater repulsions than electrons residing in 4s orbitals, with the order of increasing repulsion being:

where *V* is the potential energy due to repulsion.

Therefore, to determine the stability of an atom in the ground state, we need to consider the net effect of the relative energies of 4s/3d orbitals and the repulsion of electrons. Calculations for the overall energies of Sc show that