The scattering factor describes the amplitude of scattered rays from a single atom.
The presence or absence of an intensity peak depends on the interference of scattered X-rays at the detector of the powder X-ray diffractometer. Since the interference of scattered X-rays is the sum of the amplitudes of X-ray waves from many atoms in a sample, we must begin with the analysis of the resultant amplitude of scattered rays from a single atom (scattering factor), which is, in turn, the sum of amplitudes of waves scattered by the electrons in the atom.
The amplitude of a travelling wave is expressed by the equation:
We can also expressed the general wave equation in its complex form:
The complex form of the wave equation is equivalent to the travelling wave equation if we consider only the real part of it: Re(y), which is the value that is physically observed in an X-ray diffraction experiment. The reason eq25 is preferred over the travelling wave equation is that it is easier to manipulate mathematically to derive the scattering factor. Recall that ω = 2π/T (angular frequency), k = 2π/λ (wave number) and Φ is the phase difference. If we assume that the scattering of X-rays by an atom is elastic, i.e. there is no change in frequency of the X-ray between the incident and scattered rays, the term kx–ωt becomes a constant and we can simplify eq25 to:
where A’ = Aei(kx-ωt).
The amplitudes of the scattered X-rays not only differ in terms of their phase as suggested by eq26 but are also proportional to the number of electrons in the atom, ρdV, where ρ and V are electron density and volume of the atom respectively. If we define A’ as the number of electrons in the atom, eq26 becomes
where the amplitude of the scattered X-rays from an atom is denoted by f, the scattering factor of an atom.
To determine an expression for Φ, we note that the ratio of path difference δ and wavelength is equal to the ratio of phase difference and 2π, i.e.
Substitute eq19 in eq28,
Since and from eq23, , eq29 becomes:
In three dimensions, we let a = r and IaI = IrI = r,
Substitute eq30 in eq27
where
Since ρ is spherically symmetrical, we can represent the volume element dV in eq31 in spherical coordinates where dV = r2sinμdrdμdΦ (see above diagram). Eq31 becomes:
Integrating both sides,
Note that d(cosμ) = -sinμdμ; when μ = π, cosμ = -1; when μ = 0, cosμ = 1. So the second integral in eq32 becomes
Eq32 now becomes
Since
where . ρ is a function of r and remains within the integral.
So far, we have developed an expression (eq33) that describes the resultant amplitude of scattered rays from a single atom. To further analyse the interference of scattered X-rays from multiple atoms in a sample, we have to derive another expression called the structure factor.